plsssss ans fstt tomorrow my exam is there
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Area of quadrilateral =1/2d(h1+h2
the diagonal =30cm
and 1st height =8
and then 2nd height =10
so we know that area of quadrilateral =1/2diagonal(h1+h2)
1/2*30*(10+8)
15*18=270cm²
hope it's helpful to u
the diagonal =30cm
and 1st height =8
and then 2nd height =10
so we know that area of quadrilateral =1/2diagonal(h1+h2)
1/2*30*(10+8)
15*18=270cm²
hope it's helpful to u
Answered by
1
Answer:
Area of quadrilateral = 270 C.M^2
Step-by-step explanation:
Hey Mate,
Given,
Length of diagonal = 30 cm
Length of perpendicular = 8 cm and 10 cm .
So ,
Area of quadrilateral =
1 / 2 × length of diagonal ( sum of perpendiculars )
= 1 / 2 × 30 × ( 8 + 10 )
= 15 × 18
= 270 cm^2
THANK-YOU
. ☺
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