Math, asked by reddypmeghana, 8 months ago

Plssssss ans correct and fast

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Answered by gumapathi9865
2

Answer:

Angle CDE=ABC. (Vertically opposite angles are equal)

hence ,ABC=45°

sum of three angles in a triangle is 180°.

CAB+ABC+ACB=180°

45°+45°+X=180°

90°+X=180°

X=180°-90°

X=90°

Therefore ACB=90°

Hope this will help you.

Answered by ItzDvilJatin2
17

</u></strong><strong><u>{\bigstar}Given

AB is parllel to DE

Angle EDC = 45⁰

Angle CAB = 45⁰

</u><u>{\bigstar}To Find

Angle ACB =?

</u><u>{\bigstar}solution

Angle B = Angle D = 45⁰

Angle ACB + Angle CBA + Angle BAC = 180⁰. (Angle sum property)

Angle ACB + 45⁰ + 45⁰ = 180

Angle ACB + 90⁰ = 180⁰

Angle ACB = 90⁰

HOPE IT HELPS

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