Math, asked by Shraddhakothari, 1 year ago

plssssss ans thisssss

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Answered by vampire002

hey mate here is your answer
so tan a =7/24 = BC/ab
let the common multiple be X
so BC=7x and ab=24x
so by Pythagoras theorem
ac²=ab²+bc²
=576x²+49x²
=625x²
ac=25x
so cosec a = ac/bc
=25x/7x
=25/7
now put it in required equation
so,1/√(cosec²a-1)= 1/√((625/49)-1)=
1/√(576/49)=
1/24/7=7/24
hope it will help you
mark me brainliest

Shraddhakothari: ty

Shraddhakothari: sry but i cant tell u that from where i m coz this is a app just for helping in studies

Shraddhakothari: but tysm for the ansss

Shraddhakothari: N sry if i disturbed u coz its ur 10th

vampire002: ok bye

Shraddhakothari: heyy 1 doubt

Shraddhakothari: here i ur sum

Shraddhakothari: 1/root 625/49-1 and in next step u have written 1/root 576/49

Shraddhakothari: how is it so

vampire002: This is because the sum is like this (625/49)-1/1. so by so this equation by cross multiplication we get (576/49)

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