Question

plssssss help me in Q pls I beg u

Answer 1

Answer:

a) 18m/s

b) No acceleration i.e there I no change in speed.

c) -5.8 $m/s^{2}$

Explanation:

a) Observe the graph carefully, the x-axis is time and the y-axis is speed. Here the question has asked us the speed of the car at 0s. Which means simply whatever the speed is on y-axis. i.e The speed will be the starting point of the slope in the graph (a horizontal line can also be considered a slope). Hence, your answer is 18 m/s from observation.

b) Since the slope is a straight line parallel to x-axis in between the time intervals 0s and 0.9s, hence there is no change in y-axis, i.e no change in speed. Hence No acceleration i.e there I no change in speed.

c) The acceleration of a speed-time graph is the slope of that graph. Hence the slope between the time intervals 0.9s and 4s will give us the acceleration.

⇒ Slope of a graph is given by :  $\frac{x_{2} -x_{1} }{y_{2}- y_{1} }$  (where x and y represents the coordinates of the points)

⇒ acceleration of the car = $\frac{0-18}{4-0.9} = \frac{-18}{3.1}$ = -5.8 $m/s^{2}$ (approx.)

For question a) and b) don't write my explanation but for c) write the explanation in a little more formal way.

Hope it helps :)

(If you find any mistakes, which I am sure there aren't any, then please contact me within 10 minutes of writing this answer, if not possible, please forgive me)

If you have any other queries, feel free to disturb me again.