Plsssssss tell all three questions....
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1st question cannot be solved as what is to be proven is not given.
2nd
Here,
a = b
Therefore b-a = 0
Hence 9(b-a) = 0
3rd
AH = AB +BC + CD + DE + EF + FG +GH.
Here AB , BC and CD are part of AH
Therefore AH>AB+BC+CD
2nd
Here,
a = b
Therefore b-a = 0
Hence 9(b-a) = 0
3rd
AH = AB +BC + CD + DE + EF + FG +GH.
Here AB , BC and CD are part of AH
Therefore AH>AB+BC+CD
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