plssssssss answer the question from polynomials
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Answer:hhnvjfjchf jcufufufufyxgdg hchcufh
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amrita91:
plssss answer
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If zeros are reciprocals, then their product is 1.
So 6a/(a^2+9)=1
6a = a^2 + 9
a^2-6a+9=0
(a-3)^2=0
a=3
So the value of a is 3
So 6a/(a^2+9)=1
6a = a^2 + 9
a^2-6a+9=0
(a-3)^2=0
a=3
So the value of a is 3
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