Question

Plssssssss answer this question ....i'll mark correct one as brainliest

A particle was at rest from 9am to to 9:30 am .it moved at a uniform speed of 10 km / h from 9:30 to 10:00 am find the average speed between 9:00am to 10:00 am and 9:50 am to 10:00 am.

Answer 1

Hey !!!

let at point A a particled is reached at B point

A(9:30 )time ________________B(10:0) Am

•°• Then time taken 10 :0 - 9;30 = 30 min time taken to reach at B point .

Speed given :- 10km/h
time = 30min /1/2hour

Distance cover A to B = speed ×time

=> 10×1/2 = 5km

Now 1st we want to find average speed at 9Am to 10AM but at 9:AM to 10AM particle is not move so distance = 0
And 9:30to 10:00 Am = 5km
Hence

total distance / total time = average speed

0+5/1 = Average speed

5km/h = Average speed 9:Am to 10Am

now 2nd condition is that we wants to find speed between 9:50 to 10;0Am

here given time = 10min = 10/60 = 1/6h
speed = 10km speed was uniform 9:30 to 10:00 Am
so 9:50AM to 10:00 Am so speed = 10km/h

hence average speed 9:50 Am to 10:0Am Answer

If you want to find speed between 9:50 to 10:00 AM

then distance = 5×1/6 = 5/6 km

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Hope it helps you !!!

@Rajukumar111