Question

plsssssssssss...... answer my questions​

Answer 1

$1. {({2}^{ - 1} \times {5}^{ - 1})}^{2} \times {(\frac{ - 5}{8})}^{ - 1} \\ \\ = ({\frac{1}{2} \times \frac{1}{5}})^{2} \times ( \frac{ - 8}{5} ) \\ \\ = {( \frac{1}{10}) }^{2} \times \frac{ - 8}{5} \\ \\ = \frac{1}{100} \times \frac{ - 8}{5} \\ \\ = \frac{ - 4}{250}$

$2.{({6}^{ - 1} - {8}^{ - 1} )}^{ - 1} + {( {2}^{ - 1} - {3}^{ - 1} )}^{ - 1} \\ \\ = {(\frac{1}{6} - \frac{1}{8})}^{ - 1} + {( \frac{1}{2} - \frac{1}{3})}^{ - 1} \\ \\ = {(\frac{1}{24})}^{ - 1} + { (\frac{1}{6})}^{ - 1} \\ \\ = 24 + 6 \\ \\ = 30$

$3. {({3}^{ - 1} \times {5}^{ - 1} )}^{ - 1} \div {(6)}^{ - 1} \\ \\ = {(\frac{1}{3} \times \frac{1}{5})}^{ - 1} \div \frac{1}{6} \\ \\ = {(\frac{1}{15} )}^{ - 1} \times 6 \\ \\ = 15 \times 6 \\ \\ = 90$

$4.{( {4}^{ - 1} + {8}^{ - 1})}^{1} \div {(\frac{2}{3})}^{ - 1} \\ \\ = \frac{1}{4} + \frac{1}{8} \div \frac{3}{2} \\ \\ = \frac{3}{8} \div \frac{3}{2} \\ \\ = \frac{3}{8} \times \frac{2}{3} \\ \\ = \frac{1}{4}$

RULES INVOLVED :-

(a/b)^ -1 = (b/a)

a/b + c/d = (ad+bc)/db

a/b - c/d = (ad - bc)/bd

a/b ÷ c/d = a/b * d/c