Question

Plsssssssssss solve this question.

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Answer 1

Answer:

(2) $AC^{2} = AB^{2} + BC^{2}$

Statement 2 is true.

Explanation:

In Δ ABC,

∠A + ∠B + ∠C = 180°            [ Angle sum property of triangle]

⇒ 50°  + 40 ° +  ∠B = 180°

⇒ 90° +  ∠B = 180°

⇒ ∠B = 180° -  90°  

⇒ ∠B = 90°

∴Δ ABC is a right triangle right angled at B.

Thus, in Δ ABC, By Pythagoras theorem,

$AC^{2} = AB^{2} + BC^{2}$

Hence, proved.

Hope you got that.

Thank You.

Answer 2

Step-by-step explanation:

If n[P(A)]=256,find n(A)