Question

plssssssssssss answer these its serious​

Answer 1

Answer:

Step-by-step explanation:

here,

i) Consider the triangle △ADB.

∠BAD=60° and ∠ABD<∠ABC⟹∠ABD<60°

Now, In a triangle, side opposite larger angle is greater than the side opposite smaller angle.

Hence, as BD is opposite ∠BAD, AD is opposite ∠ABD and we saw that ∠ABD<∠BAD=60°.

∴ AD<BD

ii) now, In ΔBDC.

∠BCD = 60° and ∠DBC < ∠ABC but ∠ABC = ∠ACB.

so, ∠DBC < ∠ACB it means ∠DBC < 60°.

∴ ∠BDC > ∠BCD > ∠DBC

so, In any triangle, side opposite larger angle is greater than the side opposite smaller angle.

Hence, as BD is opposite ∠BCD, BC is opposite ∠BDC.

∴ BC > BD                 [ from above]

hope it will help you.