Question

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Answer 1

Answer:

[(x-1)(x-2)(x²-9x+14)] / [(x-7)(x²-3x+2)]

= [(x-1)(x-2)(x²-2x-7x+14)] / [(x-7)(x²-x-2x+2)]

= [(x-1)(x-2){x(x-2)-7(x-2)}] / [(x-7){x(x-1)-2(x-1)}]

= [(x-1)(x-2)(x-7)(x-2)] / [(x-7)(x-1)(x-2)]

= x-2 [ since common terms got cancelled out ]

ans = (x-2)

hope it helped :)