Question

plssssssssssssssssssssssssssssssssssssssssssans
A bullet of mass 20g moving with a velocity of 200m/s gets embedded in a wooden block of mass 980g. Calculate the velocity acquired by the block.

Answer 1

Use conservation of momentum equation

initial momentum of bullet = 200 × 20 = 4000 g m/s
final mass of system= 980+20= 1000g
final velocity = v

Now, use conservation of momentum equation,
1000 × v = 4000
v = 4000/1000 = 4 m/s

Velocity acquired by block is 4m/s

Answer 2

20*200=x*980
so,
x=(20*200)/980
x=4000/98
x=40.82