Math, asked by swastikajoshi62, 2 months ago

plwase sokve ittt

write 1/81 as a power of 3​

Answers

Answered by jshivangi630
0

Answer:

CERTIFIED EDUCATOR

1/81 = 3^x

(I) Using algebraic method.

Express 81 with its prime factors.

1/3^4 = 3^x

Apply the negative exponent rule which which is 1/a^m=a^(-m) .

3^(-4)=3^x

Since both sides of the equation has the same base 3, equate the exponents of each side equal to each other.

-4=x

Hence, the solution is x=-4 .

(II) To bring down x, apply the power rule of logarithm which is

log_b m^a = a log_bm . So take the logarithm of both sides, with a base of 3.

log_3 1/81 = log_3 3^x

log_3 1/81 = x log_3 3

At the left side of the equation, apply the quotient rule of logarithm log_b (m/n) = log_b m - log_b n .

log_3 1 - log_3 81 = x log_3 3

Express 81 with its prime factors.

log_3 1 - log_3 3^4 = x log_3 3

log_3 1 - 4log_3 3 = x log_3 3

Note that a logarithm of 1 is always equal to zero ( log_b 1 = 0 ).Also, if the base and argument are the same, then the logarithm is equal to one (log_b b = 1 ).

0 -4(1) = x(1)

-4=x

Hence, x=-4 .

Answered by SamVarghese
0

1/81

= 1/3 × 3 × 3

= 1/3³

= 3‐³

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