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Given A⃗ & B⃗ are unit vectors i.e. |A⃗|=|B⃗|=1
If θ is the angle between the unit vectors A⃗ & B⃗ then the vectors (A⃗+2B⃗) & (5A⃗−4B⃗) will be perpendicular if their dot product is zero hence
(A⃗+2B⃗)⋅(5A⃗−4B⃗)=0
5A⃗⋅A⃗+10A⃗⋅B⃗−4A⃗⋅B⃗−8B⃗⋅B⃗=0
5|A⃗|2+6A⃗⋅B⃗−8|B⃗|2=0
5+6A⃗⋅B⃗−8=0(∵ |A⃗|=|B⃗|=1)
A⃗⋅B⃗=36
|A⃗||B⃗|cosθ=12
1⋅1⋅cosθ=12
cosθ=12
cosθ=cos60∘
θ=60∘
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