plx plz explanation... plz explanation
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In order to form a negatively charged colloidal sol on adding AgNO3 solution into KI solution, KI should be in excess.
Among all options, KI is in excess in option B as shown:
50 mL of 0.1 M AgNO3 + 40 mL of 0.1 M KCl
m moles of AgNO3=50×0.1=5
m moles of KI=50×0.2=10
KI is in excess
So, I− is adsorbed on AgI sol
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