ply) = my²-2y +3, Ep(-1) = 7
Lp (-1) = - m X( )Х-2 (-1) + 3
( )m+ 2 + 3
m=7-( )
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Answer refference to above diagram
let quadrilateral ABCD is rectangle
In ∆ ADC ,
AD = 6cm
DC = 8cm
AC = ?
By Pythagoras Theorem,
( hypotenuse )² = ( height )² + ( base )²
AC ² = AD² + DC²
AC² = 6² + 8²
AC ² = 36 + 64
AC² = 100
AC = 10 ---------( taking square root of booth side )
therefore, The diagonal of the rectangle is 10 cm
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