plz........................?....!!......!
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Answered by
1
(1)...2a^2-2ab+bc-ac
2a(a-b)-c(a-b)
(a-b)(2a-c)
(2)...2a(4b^2-9a^2)
is your answer
2a(a-b)-c(a-b)
(a-b)(2a-c)
(2)...2a(4b^2-9a^2)
is your answer
Answered by
1
(1)
Given Equation is 2a^2 + bc - 2ab - ac
= > 2a^2 - ac - 2ab + bc
= > a(2a - c) - b(2a - c)
= > (a - b)(2a - c)
(2)
Given Equation is 8ab^2 - 18a^3
= > 2a(4b^2 - 9a^2)
= > 2a((2b)^2 - (3a)^2)
= > 2a(3a + 2b)(3a - 2b).
Hope this helps!
Given Equation is 2a^2 + bc - 2ab - ac
= > 2a^2 - ac - 2ab + bc
= > a(2a - c) - b(2a - c)
= > (a - b)(2a - c)
(2)
Given Equation is 8ab^2 - 18a^3
= > 2a(4b^2 - 9a^2)
= > 2a((2b)^2 - (3a)^2)
= > 2a(3a + 2b)(3a - 2b).
Hope this helps!
siddhartharao77:
:-)
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