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while going
s=vt
6/2.5=t1
while coming back
s=vt
6/4=t2
therefore avg. speed=total distance/total time
=12/(6/2.5+6/4)
12*5 0/195
=40/13
s=vt
6/2.5=t1
while coming back
s=vt
6/4=t2
therefore avg. speed=total distance/total time
=12/(6/2.5+6/4)
12*5 0/195
=40/13
ketan64:
plz mark as brainliest
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b) 40/13
please mark this answer brainliest.
please mark this answer brainliest.
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please mark this answer brainliest
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