Question

Plz amswer me this answers questionAnd explain the format plz​

Answer 1

Answer:

1) (3/4)^2x+1=((3/4)^3)^3

when there r two powers given outside

You have to multiply the powers

so 3*3=9

So, 3/4^2x+1=3/4^9

Since the denominator and numerator are the same, let us take the powers out separately and calculate

2x+1=9

2x=9-1

2x=8

x=8/2

x=4

2)when the same fraction is given, and there is a multiplication sign, u have to add the powers of both

so 2/5^3×2/5^6= 2/5^3+6

= 2/5^9

again like the previous one, we'll take the powers out and calculate

9=3x

3x=9

x=9/3

x=3

3) when there is a division symbol between two same fractions, we have to subtract the powers

so -1/5^20÷-1/5^15=-1/5^5x

-1/5^20-15= -1/5^5

5=5x

x=5/5

x=1

4) 1/16×1/2^2=1/2^3(x-2)

1/16 can be written as 1/2^4 since 2 multiplied by itself four times gives 16 and 1 into itself four times gives 1

1/2^4×1/2^2=1/2^3(x-2)

1/2^4+2=1/2^3(x-2)

1/2^6= 1/2^3(x-2)

6=3(x-2)

when a number is given outside a polynomial, we should multiply it with the terms of the polynomial which in this case is x and -2

so, 6=3x-3×2

6=3x-6

6+6=3x

12=3x

x=4