Plz and 34th question.....
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PLEASE MARK BRAINLIEST IF HELPED AND ALSO JUST CHECK ONCE IF CALCULATION IS CORRECT OR NOT..
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2/x+ 3/y = 13
(2y+3x)/xy = 13
2y + 3x = 13xy
2y = 13xy- 3x
2y = x(13y-3)
2y/(13y-3) = x ----eq1
5/x-4/y= -2
(5y-4x)/xy = -2
5y-4x = -2xy
5y= 4x-2xy
5y = x(4-2y)
5y/(4-2y)= x -----eq2
from eq1 and 2,
2y/(13y-3) = 5y/(4-2y)
by cross multipying,
2y(4-2y)= 5y(13y-3)
8y - 4y^2 = 65y^2 - 15y
15y+8y = 65y^2+4y^2
23y = 69y^2
23 = 69y
y= 1/3
Then, substitute the value of y in any of the two equations.
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