Question

Plz and 34th question.....

Answer 1

Step-by-step explanation:

PLEASE MARK BRAINLIEST IF HELPED AND ALSO JUST CHECK ONCE IF CALCULATION IS CORRECT OR NOT..

Answer 2

Answer:

2/x+ 3/y = 13

(2y+3x)/xy = 13

2y + 3x = 13xy

2y = 13xy- 3x

2y = x(13y-3)

2y/(13y-3) = x ----eq1

5/x-4/y= -2

(5y-4x)/xy = -2

5y-4x = -2xy

5y= 4x-2xy

5y = x(4-2y)

5y/(4-2y)= x -----eq2

from eq1 and 2,

2y/(13y-3) = 5y/(4-2y)

by cross multipying,

2y(4-2y)= 5y(13y-3)

8y - 4y^2 = 65y^2 - 15y

15y+8y = 65y^2+4y^2

23y = 69y^2

23 = 69y

y= 1/3

Then, substitute the value of y in any of the two equations.