Math, asked by arushi9046, 11 months ago

plz and fast....................​

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Answered by RohitDBawse
0

Answer:

Step-by-step explanation:

Given x = 3 – 2√2

⇒ x = 2 + 1 – 2√2

⇒ x = (√2)2 + 12 – 2 × √2 × 1

⇒ x = (√2 – 1 )2

∴ √x = (√2 – 1 )

Now consider, (1/√x) = 1/(√2 – 1 )

Multiply and divide with (√2 + 1 ), we get

(1/√x) = (√2 + 1 )/[(√2 – 1 )(√2 + 1 )]

         = (√2 + 1 )/[2 – 1]

∴  (1/√x) = (√2 + 1 )

√x + (1/√x) = (√2 – 1) + (√2 + 1) = 2√2


RohitDBawse: Hope it helps you
RohitDBawse: Mark as brainliest if you understood
arushi9046: no the ans is give as 2
RohitDBawse: oh ok
RohitDBawse: it 3 + 2 root 2
RohitDBawse: i did 3- 2 root 2
Answered by sudhayg
0

Answer:

Step-by-step explanation:

Brainly.in

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Secondary SchoolMath 5+3 pts

Plz and fast....................​

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Sudhayg · Ambitious

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RohitDBawse

RohitDBawse Ambitious

Answer:

Step-by-step explanation:

Given x = 3 – 2√2

⇒ x = 2 + 1 – 2√2

⇒ x = (√2)2 + 12 – 2 × √2 × 1

⇒ x = (√2 – 1 )2

∴ √x = (√2 – 1 )

Now consider, (1/√x) = 1/(√2 – 1 )

Multiply and divide with (√2 + 1 ), we get

(1/√x) = (√2 + 1 )/[(√2 – 1 )(√2 + 1 )]

= (√2 + 1 )/[2 – 1]

∴ (1/√x) = (√2 + 1 )

√x + (1/√x) = (√2 – 1) + (√2 + 1) = 2


arushi9046: question u have considared is wrong
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