Question

Plz and we as soon as possible

Answer 1

(2x-y-z)³+(2y-z-x)³+(2z-x-y)³,

now

(2x-y-z) + (2y-z-x) + (2z-x-y),

2x+2y+2z-2x-2y-2z,

0,

since

(2x-y-z)+(2y-z-x)+(2z-x-y)=0,

then

(2x-y-z)³+(2y-z-x)³+(2z-x-y)³

=3×(2x-y-z)(2y-z-x)(2z-x-y)