Math, asked by harkeetsingh63, 1 month ago

plz ans 15 Q
with explaination
class 9​

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Answered by wasimf14
1

Answer:

 \frac{1}{ \sqrt{5}  +  \sqrt{3} -  \sqrt{8}  }

 =   \frac{ \sqrt{5}  +  \sqrt{3} +  \sqrt{8}  }{ ({ \sqrt{5} +  \sqrt{3})  }^{2} - 8 }

 =   \frac{ \sqrt{5}  +  \sqrt{3} +  \sqrt{8}  }{5  + 2 \sqrt{15}  + 3 - 8 }

 =  \frac{ \sqrt{5} }{2 \sqrt{15} }  +  \frac{ \sqrt{3} }{2 \sqrt{15} }  +   \frac{ \sqrt{8} }{2 \sqrt{15} }

 =  \frac{1}{2 \sqrt{3} }  +  \frac{1}{2 \sqrt{5} }  +  \frac{ \sqrt{2} }{ \sqrt{15} }

 =  \frac{ \sqrt{3} }{6}  +  \frac{ \sqrt{5} }{10}  +  \frac{ \sqrt{30} }{15}

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