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first divide the % value of given element to its mass no. like iron mass is 55.8 and it % is given 69.9/55.8 so after dividation 1.25 ans same for oxygen then 30.1/16 then 1.875 and then choose the lowest value and divide the lowest value is 1.25 then for iron is 1.25/1.25=1 and for oxygen 1.875/1.25 =1.5(3/2) then emprical formula is FeO1.5(FeO3/2) so it is also wirte in this way Fe2O3 this correct one
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empirical formula....
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