Question

plz ans bato dooo yarrrrrrrrr

Answer 1

Hey user !!

Here is your answer !!

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Let F be the mid point of AC & E be the mid point of AB.

Join CE, AB, BF

In ΔABC

length of two tangents drawn from same point to the circle are equal

CF=CD=6cm

BE=BD=8cm

AE=AF=x

We observed that

AB =AE +EB =x+8

BC =BD +DC =8+6=14

CA=CF+FA=6+x

Now perimeter of circle

25=AB+BC+CA

28+2x=x+8+14+6+x

S=14+x

Area of ΔABC =√s(s-a) (s-b) (s-c)

√14+x(48x).......... 1st eq.

Area of Δ ABC =2*ar(ΔAOF +ΔCOD +ΔDOB)

=56+4x........2nd eq.

From 1st n 2nd option

√(14+x)(48x) =56+4x

squaring both sides

48x(14+x)=(56+4x)^2

48x=16(14+x)

48x=224+16x

32x=224

x=7cm

Hence, AB=x+8=7+8=15

AC =6+x=6+7=13cm
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Hope it is satisfactory :-)
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