Question

plz ans faast and correct plz ​

Answer 1

Hope it help you.

Please mark it as brainliest.

Answer 2

$\bold{In\ given\ figure,}$

$\bold{Quadrilateral\ ABCD\ is\ a\ parallelogram.}$

$\bold{So, AD ∣∣ BC}$

∴$\bold{ ∠DAC = ∠ACB}$ --- ( Alternate angle)

∴$\bold{ ∠ACB = 35}$

$\bold{∠AOB + ∠BOC = 180°}$ --- (straight angle)

⇒$\bold{72 + ∠BOC = 180° }$

∴ $\bold{∠BOC = 108°}$

In △BOC,

$\bold{∠OBC + ∠BOC + ∠OCB = 180°}$

$\bold{⇒∠OBC + 108^+ 35° = 180°}$

⇒ $\bold{∠OBC = 37°}$

∴ $\bold{∠DBC = 37}$

hope it helps ☺️