Question

plz Ans fast...........

Answer 1

Given :

1. AB = CD

2. CE = BF

3. ∠ ACE = ∠ DBF

To prove :

1. Δ ACE ≡ Δ DBF

2. AE = DF

Proof :

AB = CD

Adding BC on both sides to the above equation we get,

AB + BC = CD + BC

=> AC = BD ----( Equation 1 )

Consider Δ ACE and Δ DBF

AC = BD ( S ) ( From Equation 1 )

∠ACE = ∠ DBF ( A ) ( Given )

CE = BF ( S ) ( Given )

Therefore by SAS criteria, we can say that,

Δ ACE ≡ Δ DBF

By CPCT, ( Corresponding parts of congruent triangles ) we can say that,

AE = DF

Hence Proved