Question

plz ans fast and step by step explanation.
If sin theta + cos theta = a and sec theta +cosec theta=b , then the value of b(a²-1) is equal to​

Answer 1

Step-by-step explanation:

Given that :-

Sin theta +cos theta=a----(1)

squaring on both sides

= (Sin theta +cos theta)²=a²

=>sin²theta+cos²theta+2sin theta cos theta=a²

=>1+2sin theta cos theta=a²

=>2 sin theta cos theta=a²-1----(2)

=>sin theta cos theta =(a²-1)/2---(3)

and sec theta + Cosec theta =b

=>(1/cos theta)+(1/sin theta)=b

=>(sin theta +cos theta)/(sin theta cos theta)=b

=>a/[(a²-1)/2]=b from (1)&(3)

=>2a/(a²-1)=b

=>2a=b(a²-1)