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ok..here is ur answer..
Step-by-step explanation:
GIVEN = AB II CD
TO PROVE = GL II HM
PROOF = if GL bisects
<AGH. .... so,
<AGL = <LGH ----1
HM bisects < GHD
SO....
<GHM = <MHD ----2
now < AGL + < LGH = <GHM + <MHD ( because they are alternate angles )
Now replacing <AGL with < LGH and
< MHD with < GHM. as they are equal from eq .1 and eq.2 respectively ...
2<LGH = 2<GHM
<LGH = <GHM
So it is proved that alternate angles are equal then lines are.parallel...
GL II HM
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