Math, asked by 129045, 11 months ago

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Answered by Parulsinghal
9

Answer:

ok..here is ur answer..

Step-by-step explanation:

GIVEN = AB II CD

TO PROVE = GL II HM

PROOF = if GL bisects

<AGH. .... so,

<AGL = <LGH ----1

HM bisects < GHD

SO....

<GHM = <MHD ----2

now < AGL + < LGH = <GHM + <MHD ( because they are alternate angles )

Now replacing <AGL with < LGH and

< MHD with < GHM. as they are equal from eq .1 and eq.2 respectively ...

2<LGH = 2<GHM

<LGH = <GHM

So it is proved that alternate angles are equal then lines are.parallel...

GL II HM

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