Question

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Answer 1

Explanation :-

• Given that, 3x + y = 5 --------(1)

[ Put x = 2 in eqn. (1) ]

=> 3(2) + y = 5

=> 6 + y = 5

=> y = 5 - 6

=> y = -1

.°. (x,y) = (2,-1) .

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• 3x + y = 5 --------(1)

[ Put y = 1 in eqn. (1) ]

=> 3x + 1 = 5

=> 3x = 5 - 1

=> 3x = 4

=> x = 4/3

=> x = 1.3

.°. (x, y) = ( 1.3,1)

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• 3x + y = 5 --------(1)

[ Put x = 3 in eqn. (1) ]

=> 3(3) + y = 5

=> 9 + y = 5

=> y = 5 - 9

=> y = -4

.°. (x, y) = ( 3 , -4)

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3x + y = 5 --------(1)

[ Put y = 4 in eqn. (1) ]

=> 3x + 4 = 5

=> 3x = 5 - 4

=> 3x = 1

=> x = 1/3

=> x = 0.3

.°. (x, y) = (0.3,4)

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Answer 2

Answer:

0.3 , 4

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