Question

Plz ans fast its urgent
que in the attachment
no spamming please

Answer 1

$\underline{\large\bf{\mathfrak{Hallo!}}}$

Please refer to the attachment for the Answer.

The final answer is N = 1

$\bf{\mathfrak{Hope \: this \: helps...:)}}$

Answer 2

Given,

$N = \frac{\sqrt{\sqrt{5} +2}\ +\ \sqrt{\sqrt{5} -2}}{\sqrt{\sqrt{5} +1}} \ \ - \ \sqrt{3 - 2\sqrt{2}} \\ \\ N = N_1(say) - \ \sqrt{3 - 2\sqrt{2}} \\ \\ \text{Now,} \\ \\ N_1 = \frac{\sqrt{\sqrt{5} +2}\ +\ \sqrt{\sqrt{5} -2}}{\sqrt{\sqrt{5} +1}} \\ \\ \text{Making square of both sides} \\ \\ (N_1)^{2} = \frac{\sqrt{5} +2 +\sqrt{5} -2 + 2\sqrt{\sqrt{5} +2} \ \sqrt{\sqrt{5} -2}}{\sqrt{5} +1} \\ \\ (N_1)^{2} = \frac{2\sqrt{5} + 2\sqrt{5-4}}{\sqrt{5} +1} \\ \\ (N_1)^{2} = \frac{2(\sqrt{5} + 1)}{\sqrt{5} + 1} \\ \\ (N_1) = \sqrt{2} \\ \\ So, \\ \\ N = N_1 - \sqrt{3 - 2\sqrt{2}} \\ \\ N = \sqrt{2} -\sqrt{1 + (\sqrt{2})^{2} - 2\sqrt{2}} \\ \\ N = \sqrt{2} -\sqrt{(1 -\sqrt{2})^{2}} ................(i) \\ \\ N = \sqrt{2} -\frac{+}{}(1 -\sqrt{2})} \\ \\ \text{Taking +ve} \\ \\ N = \sqrt{2} - 1 + \sqrt{2} \\ \\ N = 2\sqrt{2} - 1 \\ \\ \text{Taking -ve} \\ \\ N = \sqrt{2} + 1 - \sqrt{2} \\ \\ N = 1 \\ \\ \textbf{N = 1}$