plz Ans fast ....... no. 2
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let initially speed is u
by formula
s = ut+1/2at²
in first second total distance traveled = 1m
in second sec = 2.10m
in 3rd = 3.30m
so
1 = u + 1/2a
2.1 = 2u + 2a
______________
2 = 2u + a
2.1 = 2u + 2a
______________
a = 0.1m/s²
so
F = ma
F = 0.250×0.1
____________
F = 0.025
= 2.5×10-²
hope it helps you
@di
by formula
s = ut+1/2at²
in first second total distance traveled = 1m
in second sec = 2.10m
in 3rd = 3.30m
so
1 = u + 1/2a
2.1 = 2u + 2a
______________
2 = 2u + a
2.1 = 2u + 2a
______________
a = 0.1m/s²
so
F = ma
F = 0.250×0.1
____________
F = 0.025
= 2.5×10-²
hope it helps you
@di
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