Question

plz ans fast plzz fast ​

Answer 1

$\bigstar$ Question:

• Factorise ( y² + 2y - 3)

$\bigstar$ Solution:

Here,

$\rightarrow$ ( y² + 2y - 3)

( Product = (-3) , Sum = 2y. So the numbers are (+3 ) and (-1))

$\rightarrow$ ( y² + 3y - y - 3)

$\rightarrow$ y ( y + 3 ) -1 ( y + 3 )

( By taking ( y + 3 ) common )

$\rightarrow$ ( y + 3 ) ( y - 1 )

$\bigstar$ Answer:

• Therefore, the answer is (y + 3) (y - 1) and henceforth option (a) ( y - 1 ) ( y + 3 ) is correct.