Question

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Answer 1

Answer:

(a) H2SO5 by conventional method.

Let x be the oxidation number of S

2(+1)+x+5(−2)=0

x=+8

+8 Oxidation state of S is not possible as S cannot have oxidation number more than 6. The fallacy is overcomed if we calculate the oxidation number from its structure HO−S(O2)−O−O−H.

−1+X+2(−2)+2(−1)+1=0

x=+6

(b) Dichromate ion

Let x be the oxidation number of Cr in dichromate ion

2x+7(−2)=−2

x=+6

Hence the oxidation number of Cr in dichromate ion is +6. This is correct and there is no fallacy.

(c) Nitrate ion, by conventional method

Let x be the oxidation number of N in nitrate ion.

x+3(−2)=−1

From the structure O−−N+(O)−O−

x+1(−1)+1(−2)+1(−2)=0

x=+5

Thus there is no fallacy.

Explanation:

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Answer 2

Answer:

there is no falacy..............