plz ans. in method ..... from RD Sharma of class 10th
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HEYA!!!!
OPTION NUMBER B IS CORRECT ANSWER
OPTION NUMBER B IS CORRECT ANSWER
Answered by
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hey there,
Solution : Let the radius of the circle be rr and side of the square be a.
Then, according to question, 2πr=4a2πr=4a => a=2πr4a=2πr4 =πr2=πr2 ----(i)
Now, ratio of their areas, πr2πr2 and a2a2 => πr2πr2 and (πr4)2(πr4)2 [From eq(i)] => πr2πr2 and π2r24π2r24
Therefore, Area of the circle > Area of the square Report Error to the answer is B
Hope this helps!
Solution : Let the radius of the circle be rr and side of the square be a.
Then, according to question, 2πr=4a2πr=4a => a=2πr4a=2πr4 =πr2=πr2 ----(i)
Now, ratio of their areas, πr2πr2 and a2a2 => πr2πr2 and (πr4)2(πr4)2 [From eq(i)] => πr2πr2 and π2r24π2r24
Therefore, Area of the circle > Area of the square Report Error to the answer is B
Hope this helps!
smartcow1:
can i please get brainliest?
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