plz ans it fast i will mark as brainliest!! what will be the least number of planks ,if three pieces of timber 42m,49m,and 63m long have to be divided into planks of the same length.
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given
length of 3 planks = 42m,49m,63m
by prime factorization
42 = 2*3*7
49 = 7*7
63= 3*3*7
H. C. F = 7
length of divided planks = 7m
least no of planks = 42+49+63/7
154/ 7 = 22
so 22 planks is the answer
length of 3 planks = 42m,49m,63m
by prime factorization
42 = 2*3*7
49 = 7*7
63= 3*3*7
H. C. F = 7
length of divided planks = 7m
least no of planks = 42+49+63/7
154/ 7 = 22
so 22 planks is the answer
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The answer is 22 planks......
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