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Given,
First term ( a ) = ( -8 )
Sum of n terms = 52
Common difference( d ) = ( -6 ) - ( -8 ) = -6 + 8 = 2.
Let the number of terms is n.
No. of terms = n.
=> Sum of n terms = ( n/2 ) [ 2a + ( n - 1 )d ]
=> 52 = ( n/2 ) [ 2 × ( -8 ) + ( n - 1 )2 ]
=> 52 × 2 = n [ -16 + 2n - 2 ]
=> 104 = n ( 2n - 18 )
=> 104 = 2n² - 18n
=> 2 × 52 = 2( n² - 9n )
=> 52 = n² - 9n
=> n² - 9n - 52 = 0
=> n² - 13n + 4n - 52 = 0
=> n( n - 13 ) + 4 ( n - 13 ) = 0
=> ( n - 13 ) ( n + 4 ) = 0
•°• n = 13 or -4
Since, number of terms in an A.P. can't be negative.
So, n = 13.
b. ) 13
Given,
First term ( a ) = ( -8 )
Sum of n terms = 52
Common difference( d ) = ( -6 ) - ( -8 ) = -6 + 8 = 2.
Let the number of terms is n.
No. of terms = n.
=> Sum of n terms = ( n/2 ) [ 2a + ( n - 1 )d ]
=> 52 = ( n/2 ) [ 2 × ( -8 ) + ( n - 1 )2 ]
=> 52 × 2 = n [ -16 + 2n - 2 ]
=> 104 = n ( 2n - 18 )
=> 104 = 2n² - 18n
=> 2 × 52 = 2( n² - 9n )
=> 52 = n² - 9n
=> n² - 9n - 52 = 0
=> n² - 13n + 4n - 52 = 0
=> n( n - 13 ) + 4 ( n - 13 ) = 0
=> ( n - 13 ) ( n + 4 ) = 0
•°• n = 13 or -4
Since, number of terms in an A.P. can't be negative.
So, n = 13.
b. ) 13
27jenny:
tq so much
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