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12 (i) 20/35
(ii) 0/35
15 (i) 4/5
(ii) 0/35
(iii) 5/5
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number of students who like A.E.=20 let this event be A
number of students who dislike A.E. = 15 let this event be B
total = 35 let the total be called S
P[A]=n[A]/n[S]
P[A]=20/35=4/7
P[B]=15/35= 3/7
therefore probability of students who like A.E. is 4/7 and dislike A.E. are 3/7
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