Math, asked by AdityaNegi07, 8 months ago

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Answered by MANAN8055
0

12 (i) 20/35

(ii) 0/35

15 (i) 4/5

(ii) 0/35

(iii) 5/5

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Answered by qamar24567890
0

number of students who like A.E.=20 let this event be A

number of students who dislike A.E. = 15 let this event be B

total = 35 let the total be called S

P[A]=n[A]/n[S]

P[A]=20/35=4/7

P[B]=15/35= 3/7

therefore probability of students who like A.E. is 4/7 and dislike A.E. are 3/7

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