Plz ans my que fast...........
Attachments:
Answers
Answered by
3
let radius=5x,
height=12x,
volume of the cone=2512,
1/3 πr²h=2512,
1/3 × 3.14 × 5x × 5x × 12x =2512,
3.14 × 5×5× 4×x³=2512,
3.14×100×x³=2512,
then
x³=2512/314,
x³=8,
x=³√8,
then
x=2,
then
radius=5×2=10 cm,
height=12×2=24 cm,
then
slant height=26 cm,
therefore
C.S.A of the cone =πrl,
=3.14 × 10 × 26,
=816.4 cm²,
T.S.A of the cone =πr(l+r),
=3.14×10(26+10),
=3.14×10×36,
=1130.4 cm²
height=12x,
volume of the cone=2512,
1/3 πr²h=2512,
1/3 × 3.14 × 5x × 5x × 12x =2512,
3.14 × 5×5× 4×x³=2512,
3.14×100×x³=2512,
then
x³=2512/314,
x³=8,
x=³√8,
then
x=2,
then
radius=5×2=10 cm,
height=12×2=24 cm,
then
slant height=26 cm,
therefore
C.S.A of the cone =πrl,
=3.14 × 10 × 26,
=816.4 cm²,
T.S.A of the cone =πr(l+r),
=3.14×10(26+10),
=3.14×10×36,
=1130.4 cm²
Anonymous:
Ohk.. tuo itna gussa kyu hote ho..
Similar questions