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2x+30=4x-50
2x-4x=-50-30
-2x=-80
x=80/2
x=40
2x-4x=-50-30
-2x=-80
x=80/2
x=40
ajitesh48:
are you sure right ans
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Answer :
Given,
AB||CD
Angle POA = 2x + 30
Angle CQO = 4x - 50
To find,
x
Main solution:
PR is a transversal .
Since AB||CD , angle POA = CQO because they are corresponding angles.
2x + 30 = 4x - 50
Solving for x using transposition
2x - 4x = - 50 - 30
- 2x = -80
2x = 80
x = 40° ( Answer )
Given,
AB||CD
Angle POA = 2x + 30
Angle CQO = 4x - 50
To find,
x
Main solution:
PR is a transversal .
Since AB||CD , angle POA = CQO because they are corresponding angles.
2x + 30 = 4x - 50
Solving for x using transposition
2x - 4x = - 50 - 30
- 2x = -80
2x = 80
x = 40° ( Answer )
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