Physics, asked by rakhij557, 5 hours ago

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Answered by TrustedAnswerer19
3

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 \displaystyle \int \:  {(x +  \frac{1}{x}) }^{2}  \: dx \\  =  \int \: ( {x}^{2}  + 2 +  \frac{1}{{x}^{2} } ) \: dx \\ =   \int \:  {x}^{2}  \: dx +  \int \:2 \: dx +  \int \: \frac{1}{ {x}^{2} }  \: dx \\  =   \frac{ {x}^{3} }{3}  + 2x  -  \frac{1}{x}  + c

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