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Q1. Find the value of k for which the points (3k-1, k-2) (k, k-7) and (k-l, -k-2) are collinear.
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It was very complicated question and important also .
I take more time to solve it . But finally I got my answer...........
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answer k=3
Step-by-step explanation:
slope of line AB=k-7-k+2÷k-3k+1=-5÷-2k+1------eqn 1
as points are collinear
so,
-5÷-2k+1=-k-2-k+7÷k-1-k
so, after solving it
answer: k=3
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