plz ans ques 29. urgent help
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All figures have the same area. So area of circle = area of any other partial triangle.
Area of ABC = 2 times area of circle
Therefore,
πr² = ¼*22*22
22÷7 * r² = ¼*22*22
r² = ¼*22*7
r² = 77÷2 = 38.5
r = 6.20cm
Circumference = 2*π*r
= 2*3.14*6.20
= 38.93
Now let O be the centre of circle.
So, PO = PR = 6.20cm
And, AP = RC = x
So, 2x + 6.20 + 6.20 = √2*22 [ diagonal of square]
2x + 12.40 = 31.11
2x = 18.71 = 18.70(rounded)
x = 9.35
So perimeter = 22+9.35+½πr+9.35
= 22+18.7+9.7
= 50.4
Area of ABC = 2 times area of circle
Therefore,
πr² = ¼*22*22
22÷7 * r² = ¼*22*22
r² = ¼*22*7
r² = 77÷2 = 38.5
r = 6.20cm
Circumference = 2*π*r
= 2*3.14*6.20
= 38.93
Now let O be the centre of circle.
So, PO = PR = 6.20cm
And, AP = RC = x
So, 2x + 6.20 + 6.20 = √2*22 [ diagonal of square]
2x + 12.40 = 31.11
2x = 18.71 = 18.70(rounded)
x = 9.35
So perimeter = 22+9.35+½πr+9.35
= 22+18.7+9.7
= 50.4
ÙjjwalĐhàŕìwåļ:
thnx dude
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