Plz ans ques no 5 its urgent
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Use cyclic quadrilateral property in which sum of the opposite angle of cyclic quadrilateral is 180
here
Angle bad plus angle dcb equals to 180
therfore angle dcb equals to 95
now bcf or bf is a straight line so
angle dcb plus angle x equals to 180 so angle x equals to 85
now again by the cylic quadrilateral property sum of the angles x and y equals to 180 therefore y equals to 95
here
Angle bad plus angle dcb equals to 180
therfore angle dcb equals to 95
now bcf or bf is a straight line so
angle dcb plus angle x equals to 180 so angle x equals to 85
now again by the cylic quadrilateral property sum of the angles x and y equals to 180 therefore y equals to 95
Answered by
1
angle BAD = 85 degree (given)
angle BCD = 180-85 (as ABCD is a cyclic quadilateral)
= 95 degree
angle DCF = x = 180-95(as the angle is on a straight line)
= 85 degree
angle DEF = y = 180-85 (as DCFE is a cyclic quadilateral)
= 95 degree
thus x=85degree y=95degree
angle BCD = 180-85 (as ABCD is a cyclic quadilateral)
= 95 degree
angle DCF = x = 180-95(as the angle is on a straight line)
= 85 degree
angle DEF = y = 180-85 (as DCFE is a cyclic quadilateral)
= 95 degree
thus x=85degree y=95degree
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