plz ans. the following 1 question thanx the above question which is full
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Given OD=8cm
OB=13cm
Firstly find DB.
Using Pythagoras Theorem, DB^2=OB^2 - OD^2. This gives DB = sqrt(105) = DE.
Without going into the complexity of angles, as in some of the existing answers, I would suggest using the property of Similar triangles. Clearly, AEB and ODB are similar right triangles. And as, DB~EB, therefore, AE~OD.
DB = sqrt(105), and EB = 2(sqrt(105))
and
as OD = 8cm, therefore AE = twice(8cm) = 16cm.
Finally, using Pythagoras Theorem in right triangle AED,
AD^2 = AE^2 + ED^2= 256 + 105= 361
Therefore, AD = sqrt(361) = 19cm.
OB=13cm
Firstly find DB.
Using Pythagoras Theorem, DB^2=OB^2 - OD^2. This gives DB = sqrt(105) = DE.
Without going into the complexity of angles, as in some of the existing answers, I would suggest using the property of Similar triangles. Clearly, AEB and ODB are similar right triangles. And as, DB~EB, therefore, AE~OD.
DB = sqrt(105), and EB = 2(sqrt(105))
and
as OD = 8cm, therefore AE = twice(8cm) = 16cm.
Finally, using Pythagoras Theorem in right triangle AED,
AD^2 = AE^2 + ED^2= 256 + 105= 361
Therefore, AD = sqrt(361) = 19cm.
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himangi48bhatia:
thanxx
welcome
here is my new question if u want to solve then.plzz
it's last question plzx
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hey mate
here's the solution
here's the solution
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plzz solve my new question it's last question
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