Question

plz ans the given ques​

Answer 1

Step-by-step explanation:

2cos68/cos22 -2cot15/5tan75 -3 tan20tan40tan50tan70/5

2sin(90-22)/cos22 -2cot(90-75)/5tan75 -3 tan(90-70)tan(90-50)tan50tan70/5

we know that,

sin(90-theta)=cos theta

cot(90-theta)=tan theta

tan(90-theta)=cot theta

2cos22/cos22 -2tan75/5tan75 -3cot70cot50tan50tan70/5

cot theta=1/tan theta

2 -2/5 -3/5

10-2-3/5

5/5

1

Hope it helps you...