Question

Plz ans the iv bit of the second question

Answer 1

SOLUTION :

$q - \frac{q + 1}{3} = \frac{q - 1}{5} + q \\ \\ = > \frac{3q - q + 1}{3} = \frac{q - 1 + 5q}{5} \\ \\ = > \frac{2q + 1}{3} = \frac{6q - 1}{5} \\ \\ = > 10q + 5 = 18q - 3 \\ \\ = > 8 = 8q \\ \\ = > q = 1$