plz ans the question
Attachments:
Answers
Answered by
2
(a) given F=-200 N
T= 1 sec
M=50
p=?
v=?
p=mv
v= u+at
F= m*a
-200= 50*a
-200/50=a
-4=a
v= 0+-4(1.0)
v= -4 m/sec
p= mv
= 50*-4
= -200
(b) given
T= 10 sec
M= 10 kg
V = 100 m/s
F = m*a
a = v-u/t
= 100-0/10
= 10
f = 10* 10
= 100 N
p= m*v
= 10*100
= 1000
(c) given
F= -2000
P= -200
V= -8
m=?
p= mv
-2000 = m(-8)
-2000/-8=m
25=m
t=?
t= v-u/a
f =ma
-2000/25=a
-80=a
-8-0/-80=0.1
I hop it helps you once you check if it is correct please follow me
Similar questions