Math, asked by meghna200646, 9 months ago

plz ans the question​

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Answered by boyinalakshmishivani
2

(a) given F=-200 N

T= 1 sec

M=50

p=?

v=?

p=mv

v= u+at

F= m*a

-200= 50*a

-200/50=a

-4=a

v= 0+-4(1.0)

v= -4 m/sec

p= mv

= 50*-4

= -200

(b) given

T= 10 sec

M= 10 kg

V = 100 m/s

F = m*a

a = v-u/t

= 100-0/10

= 10

f = 10* 10

= 100 N

p= m*v

= 10*100

= 1000

(c) given

F= -2000

P= -200

V= -8

m=?

p= mv

-2000 = m(-8)

-2000/-8=m

25=m

t=?

t= v-u/a

f =ma

-2000/25=a

-80=a

-8-0/-80=0.1

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