Question

plz ans the question I will mark u as brainlist

Answer 1

In ΔABC, by angle sum property we have

2x + 2y + ∠A = 180°

⇒ x + y + (∠A/2) = 90°

⇒ x + y = 90° – (∠A/2) à (1)

In ΔBOC, we have

x + y + ∠BOC = 180°

90° – (∠A/2) + ∠BOC = 180° [From (1)]

∠BOC = 180° – 90° + (∠A/2)

∠BOC = 90° + (∠A/2)

Answer 2

given: AO and OC are angular bisectors of angle A and C

to prove: angle BOC= 90 + 1/2 of angle A

proof : In ΔABC, by angle sum property we have

let angle A = 2x

let angle C be = 2y

in both the cases it is because AO and CO are angular bisector of angle A

2x + 2y + ∠A = 180°

⇒ x + y + (∠A/2) = 90°

⇒ x + y = 90° – (∠A/2) à (1)

In ΔBOC, we have

x + y + ∠BOC = 180°

90° – (∠A/2) + ∠BOC = 180° [From (1)]

∠BOC = 180° – 90° + (∠A/2)

∠BOC = 90° + (∠A/2

hence proved

pls mark as brainliest