plz ans this.........
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Given,
Area of Wheel=6.16m^2
Distance=572m
A/Q
Area Of Circular wheel= πr^2
6.16=π×r^2
r^2=6.16/π={6.16*7}/22
or,0.28*7=r√1.96=√1.4=1.4m
Distance Covered by Wheel in one ration= Circumstances France of wheel
=2πr=2*(22/7) *1.4
=(4.4*2) =8.8m
Number Of rotion Of Revolution wheel= 572/8.8=65.
65 is Your Answer.. Mate
Area of Wheel=6.16m^2
Distance=572m
A/Q
Area Of Circular wheel= πr^2
6.16=π×r^2
r^2=6.16/π={6.16*7}/22
or,0.28*7=r√1.96=√1.4=1.4m
Distance Covered by Wheel in one ration= Circumstances France of wheel
=2πr=2*(22/7) *1.4
=(4.4*2) =8.8m
Number Of rotion Of Revolution wheel= 572/8.8=65.
65 is Your Answer.. Mate
IshaAgrawal1:
tysm
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